Hi
same result can be achieved by
dat.ag<-aggregate(dat[ , c("DCE","DP")], by= list(dat$first.Name, dat$Name,
dat$Department) , "I")
Sorting according to the first row seems to be quite tricky. You could probably
get closer by using some combination of split and order and arranging back
chunks of data
ooo1<-order(split(dat$DCE,interaction(dat$first.Name, dat$Name, dat$Department,
drop=T))[[1]])
data.frame(sapply(split(dat$DCE,interaction(dat$first.Name, dat$Name,
dat$Department, drop=T)), rbind))[ooo1,]
Ancient.Nation.QLH Amish.Wives.TAS Auction.Videos.YME
2 0.28 NA NA
4 0.28 NA NA
1 0.54 0.59 0.57
3 0.54 0.59 0.57
however I wonder why the order according to the first row is necessary if all
NAs are on correct positions?
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of David
> Winsemius
> Sent: Friday, November 18, 2016 9:30 AM
> To: Karim Mezhoud <kmezh...@gmail.com>
> Cc: r-help@r-project.org
> Subject: Re: [R] aggregate dataframe by multiple factors
>
>
> > On Nov 17, 2016, at 11:27 PM, Karim Mezhoud <kmezh...@gmail.com>
> wrote:
> >
> > Dear all,
> >
> > the dat has missing values NA,
> >
> > first.Name Name Department DCE DP date
> > 5 Auction Videos YME 0.57 0.56 2013-09-30
> > 18 Amish Wives TAS 0.59 0.56 2013-09-30
> > 34 Ancient Nation QLH 0.54 0.58 2013-09-30
> > 53 Auction Videos YME NA NA 2013-12-28
> > 66 Amish Wives TAS NA NA 2013-12-28
> > 82 Ancient Nation QLH 0.28 0.29 2013-12-28
> > 102 Auction Videos YME 0.57 0.56 2014-03-30
> > 115 Amish Wives TAS 0.59 0.56 2014-03-30
> > 131 Ancient Nation QLH 0.54 0.58 2014-03-30
> > 150 Auction Videos YME NA NA 2014-06-28
> > 163 Amish Wives TAS NA NA 2014-06-28
> > 179 Ancient Nation QLH 0.28 0.29 2014-06-28
> >
> >
> > agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> > list(dat$first.Name, dat$Name, dat$Department) , "sort"))
>
> The closest I could get on a few attempts was:
>
> (agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> list(dat$first.Name, dat$Name, dat$Department) , function(d) { unlist(d)}))
> )
>
> Group.1 Group.2 Group.3 DCE.1 DCE.2 DCE.3 DCE.4 DP.1 DP.2 DP.3 DP.4
> 1 Ancient Nation QLH 0.54 0.28 0.54 0.28 0.58 0.29 0.58 0.29
> 2 Amish Wives TAS 0.59 NA 0.59 NA 0.56 NA 0.56 NA
> 3 Auction Videos YME 0.57 NA 0.57 NA 0.56 NA 0.56 NA
>
> I think the sort operation might be somewhat ambiguous in this instance. I
> tried:
>
> (agg <- as.data.frame(aggregate(dat[ , c("DCE","DP")], by=
> list(dat$first.Name, dat$Name, dat$Department) , function(d) {
> unlist(lapply(d,sort))}))
> )
>
> With no success, not even a sorted result.
>
> --
> David.
> >
> >
> > agg has list of value. I would separate value in different columns.
> >
> > Group.1 Group.2 Group.3 DCE DP
> > 1 Ancient Nation QLH 0.28, 0.28, 0.54, 0.54 0.29, 0.29, 0.58, 0.58
> > 2 Amish Wives TAS 0.59, 0.59 0.56, 0.56
> > 3 Auction Videos YME 0.57, 0.57 0.56, 0.56
> >
> > The goal:
> >
> > Group.1 Group.2 Group.3 DCE.1 DCE.2 DCE.3 DCE.4 DP.1 DP.2 DP.3 DP.4
> > 1 Ancient Nation QLH 0.28 0.28 0.54 0.54 0.29, 0.29,
> > 0.58, 0.58
> > 2 Amish Wives TAS NA NA 0.59, 0.59 NA
> > NA 0.56, 0.56
> > 3 Auction Videos YME NA NA 0.57, 0.57 NA
> > NA 0.56, 0.56
> >
> >
> >
> > dat <- structure(list(first.Name = structure(c(3L, 1L, 2L, 3L, 1L, 2L,
> > 3L, 1L, 2L, 3L, 1L, 2L), .Label = c("Amish", "Ancient", "Auction",
> > "Ax", "Bachelorette", "Basketball", "BBQ", "Cake", "Celebrity",
> > "Chef", "Clean", "Colonial", "Comedy", "Comic", "Crocodile", "Dog",
> > "Empire", "Extreme", "Farm", "Half Pint", "Hollywood", "House", "Ice
> > Road", "Jersey", "Justice", "Love", "Mega", "Model", "Modern",
> > "Mountain", "Mystery", "Myth", "New York", "Paradise", "Pioneer",
> > "Queer", "Restaurant", "Road", "Royal", "Spouse", "Star", "Storage",
> > "Survival", "The Great American", "Tool", "Treasure", "Wedding",
> > "Wife"), class = "factor"), Name = structure(c(43L, 47L, 29L, 43L,
> > 47L, 29L, 43L, 47L, 29L, 43L, 47L, 29L), .Label = c("Aliens",
> > "Behavior", "Casino", "Casting Call", "Challenge", "Contest",
> > "Crashers", "Crew", "Dad", "Dancing", "Date", "Disasters", "Dynasty",
> > "Family", "Garage", "Greenlight", "Gypsies", "Haul", "Hot Rod",
> > "Inventor", "Jail", "Job", "Justice", "Marvels", "Master", "Mates",
> > "Model", "Moms", "Nation", "Ninja", "Patrol", "People", "Pitmasters",
> > "Queens", "Rescue", "Rivals", "Room", "Rooms", "Rules", "Star",
> > "Stars", "Superhero", "Videos", "VIP", "Wars", "Wishes", "Wives",
> > "Wrangler"), class = "factor"), Department = structure(c(8L, 6L, 2L,
> > 8L, 6L, 2L, 8L, 6L, 2L, 8L, 6L, 2L), .Label = c("HXW", "QLH", "RAR",
> > "RYC", "SYI", "TAS", "VUV", "YME"), class = "factor"),
> > DCE = c(0.57, 0.59, 0.54, NA, NA, 0.28, 0.57, 0.59, 0.54,
> > NA, NA, 0.28), DP = c(0.56, 0.56, 0.58, NA, NA, 0.29, 0.56,
> > 0.56, 0.58, NA, NA, 0.29), date = structure(c(15978, 15978,
> > 15978, 16067, 16067, 16067, 16159, 16159, 16159, 16249, 16249,
> > 16249), class = "Date")), description = "", row.names = c(5L, 18L,
> > 34L, 53L, 66L, 82L, 102L, 115L, 131L, 150L, 163L, 179L), class =
> > "data.frame", .Names = c("first.Name", "Name", "Department", "DCE",
> > "DP", "date"))
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
> David Winsemius
> Alameda, CA, USA
>
> ______________________________________________
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
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