Dear,
I have the following list (mylist), in which I need to pass to the column 2
the name of the list itself.
So, running the follwing commands:
A= data.frame(1:2,3)
B= data.frame(1:4,3)
C= data.frame(c(1:2),c(4:5))
mylist=list(A=A,B=A,C=C)
lapply(mylist, setNames, paste(c("CaZyme")))
The output would be:
> lapply(mylist, setNames, paste(c("CaZyme")))
$A
CaZyme NA
1 1 3
2 2 3
$B
CaZyme NA
1 1 3
2 2 3
$C
CaZyme NA
1 1 4
2 2 5
3 3 6
My question is:
How could I name the second column with the name of each dataframe of the
list, such that NA would be substitute for A, B and C, respectively.
Thank you very much,
Andre
--
Andre
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
