Hi, Harold-- The short answer is "Yes"--in your example, the nextElem will always be a list with the i component equal to the next element of itx1 and the j component equal to the next element of itx2.
I posted a more detailed explanation in response to a query from David on the Microsoft TechNet forum: https://social.technet.microsoft.com/Forums/en-US/724b1dde-03e3-4fff-b061-363bc8ba1652/how-are-multiple-iterobjects-handled-by-foreach?forum=ropen Cheers, Rich Rich Calaway Release Manager Microsoft R Product Team 24/1341 +1 (425) 4219919 X19919 Message: 2 Date: Fri, 9 Dec 2016 17:15:38 +0000 From: "Doran, Harold" <hdo...@air.org> To: "r-help@r-project.org" <r-help@r-project.org> Subject: [R] "Safe" use of iterator (package iterators) Message-ID: <b08b6af0cf8ca44f81b9983eebdcd68601358f7...@dc1vex10mb01.air.org> Content-Type: text/plain; charset="iso-8859-1" I believe I now see the light vis-?-vis iterators when combined with foreach() calls in R. I have now been able to reduce computational workload to minutes instead of hours. I want to verify that the way I am using them is "safe". By safe I mean does the iterator traverse elements in the same way as I have below in my toy example to illustrate what I mean. In the first "traditional" example, I have only one index variable for the loop and so I know that the same list in r1 and r2 are always being grabbed. That is, in iteration 1 it is guaranteed to use r1[[1]] + r2[[1]]. In the example that uses the iterators, is this also guaranteed even though I now have two iterator objects? That is, will the index for element i always be the same as the index for element j when using this across many different cores? It seems to be true and in all my test cases so far I am seeing it to be true. But, that could be just luck, so I wonder if there is a condition under which that would NOT be true. Thank you Harold library(foreach) library(doParallel) cl <- makeCluster(2) registerDoParallel(cl) ### Create random data r1 <- vector("list", 20) for(i in 1:20){ r1[[i]] <- rnorm(10) } ### Create random data r2 <- vector("list", 20) for(i in 1:20){ r2[[i]] <- rnorm(10) } ### Use a for loop traditionally result1 <- vector("list", 20) for(i in 1:20){ result1[[i]] <- r1[[i]] + r2[[i]] } ### Use iterators itx1 <- iter(r1) itx2 <- iter(r2) result2 <- foreach(i = itx1, j = itx2) %dopar% { i + j } all.equal(result1, result2) Message: 4 Date: Fri, 9 Dec 2016 10:26:55 -0800 From: David Winsemius <dwinsem...@comcast.net> To: "Doran, Harold" <hdo...@air.org> Cc: "r-help@r-project.org" <r-help@r-project.org> Subject: Re: [R] "Safe" use of iterator (package iterators) Message-ID: <f5e6b19c-1c53-427b-8bcf-0739ddc63...@comcast.net> Content-Type: text/plain; charset=iso-8859-1 > On Dec 9, 2016, at 9:15 AM, Doran, Harold <hdo...@air.org> wrote: > > I believe I now see the light vis-?-vis iterators when combined with > foreach() calls in R. I have now been able to reduce computational workload > to minutes instead of hours. I want to verify that the way I am using them is > "safe". By safe I mean does the iterator traverse elements in the same way as > I have below in my toy example to illustrate what I mean. > > In the first "traditional" example, I have only one index variable for the > loop and so I know that the same list in r1 and r2 are always being grabbed. > That is, in iteration 1 it is guaranteed to use r1[[1]] + r2[[1]]. > > In the example that uses the iterators, is this also guaranteed even though I > now have two iterator objects? That is, will the index for element i always > be the same as the index for element j when using this across many different > cores? > > It seems to be true and in all my test cases so far I am seeing it to be > true. But, that could be just luck, so I wonder if there is a condition under > which that would NOT be true. > > Thank you > Harold > > > library(foreach) > library(doParallel) > cl <- makeCluster(2) > registerDoParallel(cl) > > ### Create random data > r1 <- vector("list", 20) > for(i in 1:20){ > r1[[i]] <- rnorm(10) > } > > ### Create random data > r2 <- vector("list", 20) > for(i in 1:20){ > r2[[i]] <- rnorm(10) > } > > ### Use a for loop traditionally > result1 <- vector("list", 20) > for(i in 1:20){ > result1[[i]] <- r1[[i]] + r2[[i]] > } > > ### Use iterators > itx1 <- iter(r1) > itx2 <- iter(r2) > > result2 <- foreach(i = itx1, j = itx2) %dopar% { > i + j > } > > all.equal(result1, result2) I wasn't sure how this would or should behave. I'm not an experienced user, merely a reader of help pages. Neither the help page, not the vignette references on the help page answered my questions in this case. I expected that call would behave analogously to the behavior of mapply when given iterators of unequal length. (The shorter of the objects is recycled to reach the length of the longer object.) That expectation was not realized. It appears that the length of first object of the objects determines computation length, but that missing values will not be recycled for the shorter iterator. An error is not reported, but rather numeric(0) is returned. So in one sense the %dopar% version is "safer" at least to the extent of not failing with an error that would have occurred when using a for-loop. This was my test case: r1 <- vector("list", 10) for(i in 1:20){ r1[[i]] <-20:29+i*10 # random numbers are not good for determining sequences of operations } r2 <- vector("list", 20) for(i in 1:10){ r2[[i]] <- 1:10 +i } itx1 <- iter(r1) itx2 <- iter(r2) result2 <- foreach(i = itx1, j = itx2) %dopar% { i + j } result2 -- David Winsemius Alameda, CA, USA ------------------------------ Message: 5 Date: Fri, 9 Dec 2016 18:42:10 +0000 From: "Doran, Harold" <hdo...@air.org> To: "'David Winsemius'" <dwinsem...@comcast.net> Cc: "r-help@r-project.org" <r-help@r-project.org> Subject: Re: [R] "Safe" use of iterator (package iterators) Message-ID: <b08b6af0cf8ca44f81b9983eebdcd68601358f7...@dc1vex10mb01.air.org> Content-Type: text/plain; charset="iso-8859-1" That is a helpful, and important, caveat. So, perhaps I should amend my original question to ask something like is it safe *when* length(r1) == length(r2) ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.