Another way to do it (a more or less straightforward translation of what you
said):
fun <- function(x) {
xp <- c("", x)[-(length(x)+1)] # to get the "previous
element of x"
x[1] <- if(x[1]=="i") "l" else x[1]
x <- ifelse(x == "i" & xp == "c", "l", x)
x <- ifelse(x == "i" & xp == "i", "h", x)
x
}
fun(X$colb)
-- or if I understood you correctly, you would actually want this to be done
separately within each level of cola: unlist(tapply(X$colb, X$cola, fun))
Kenn
On Fri, Jun 27, 2008 at 12:17 PM, poul <[EMAIL PROTECTED]> wrote:
>
> Hello every body,
> I am quite a new user of R so I beg your pardon for this naive question and
> the lake of syntax with wich I ask it:
>
> I have a data frames like this:
>
> cola colb
> 1 c
> 1 i
> 1 i
> 1 c
> 2 i
> 2 c
> 2 c
> 2 i
> 2 i
> ...
> 10000
>
> I would like ,for each level of cola and for x in colb:
>
> -if colb[x]=="i" and colb[x-1] does not exist (first row in dataframes),
> then replace colb[x] by "l"
> -if colb[x]=="i" and colb[x-1]=="c" (previous row in data frmes), then
> replace colb[x] by "l"
> -if colb[x]=="i" and colb[x-1]=="i" (previous row in data frmes), then
> replace colb[x] by "h"
>
> Thanks in advance
>
> Paul
>
> --
> View this message in context:
> http://www.nabble.com/change-values-in-data-frames-tp18151205p18151205.html
> Sent from the R help mailing list archive at Nabble.com.
>
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