> On Apr 13, 2017, at 7:56 AM, Mohammad Tanvir Ahamed via R-help > <r-help@r-project.org> wrote: > > Hi, > I have a list like > kk<- list (a = 1:5, b = 6:10, c = 4:11) > > Now i want to merger (Union) the list element "a" and "c" by name . > > My expected outcome is > kk1<- list(a_c = 1:11, b = 6:10) > > > I can do it with several lines of code. But can any one have idea to do > efficiently/ quickly on a big data with less code.
Given that you used the term in your problem specification, it's hard to understand how you missed finding the `union` function : kk1 <- with( kk, list( a_c <- union(a,c), b=b) ) kk1 #----- [[1]] [1] 1 2 3 4 5 11 10 9 8 7 6 $b [1] 10 9 8 7 6 #----- (It's not a `merge`.) I thought this would remove any factor-stored information, since the code (before bytecode compilation) is: function (x, y) unique(c(as.vector(x), as.vector(y))) But 'as.vector' does the equivalent of 'as.character' on factor vectors, so you would be "safe" from that concern. -- David. > Thanks in advance. > > Tanvir Ahamed > Göteborg, Sweden | mashra...@yahoo.com > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. David Winsemius Alameda, CA, USA ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.