Hi All,
I am using factors in a study for the social sciences.
I discovered the following:
-- cut --
library(dplyr)
test1 <- c(rep(1, 4), rep(0, 6))
d_test1 <- data.frame(test)
test2 <- factor(test1)
d_test2 <- data.frame(test2)
test3 <- factor(test1,
levels = c(0, 1),
labels = c("WITHOUT Contact", "WITH Contact"))
d_test3 <- data.frame(test3)
d_test1 %>% filter(test1 == 0) # works OK
d_test2 %>% filter(test2 == 0) # works OK
d_test3 %>% filter(test3 == 0) # does not work, why?
myf <- function(ds) {
print(levels(ds$test3))
print(labels(ds$test3))
print(as.numeric(ds$test3))
print(as.character(ds$test3))
}
# This showsthat it is not possible to access the original
# values which were the basis to build the factor:
myf(d_test3)
-- cut --
Why is it not possible to use a factor with labels for filtering with the
original values?
Is there a data structure that works like a factor but gives also access
to the original values?
Kind regards
Georg
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