... and Marc's solution is **much** better than mine. -- Bert Bert Gunter
"The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, Aug 2, 2017 at 5:59 PM, Bert Gunter <bgunter.4...@gmail.com> wrote: > ... Or if you just want to stick with basic regex's without extra packages: > >> x <- "\"cm_ffm\":\"563.77\"" >> sub("[^[:digit:]]*([[:digit:]]*.?[[:digit:]]*).*","\\1",x) > > [1] "563.77" > > Cheers, > Bert > > > > On Wed, Aug 2, 2017 at 5:16 PM, Ismail SEZEN <sezenism...@gmail.com> wrote: >> >>> On 3 Aug 2017, at 02:59, Christofer Bogaso <bogaso.christo...@gmail.com> >>> wrote: >>> >>> Hi again, >>> >>> I am struggling to extract the number part from below string : >>> >>> "\"cm_ffm\":\"563.77\"" >>> >>> Basically, I need to extract 563.77 from above. The underlying number >>> can be a whole number, and there could be comma separator as well. >>> >>> So far I tried below : >>> >>>> library(stringr) >>> >>>> str_extract("\"cm_ffm\":\"563.77\"", "[[:digit:]]+") >>> >>> [1] "563" >>> >>>> >>> >>> However, above code is only extracting the integer part. >>> >>> Could you please help how to achieve that. Thanks, >> >> >> library(readr) >> parse_number('"cm_ffm":"563.77”') >> >> ______________________________________________ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.