> On Sep 18, 2017, at 5:13 AM, Therneau, Terry M., Ph.D. <thern...@mayo.edu>
> wrote:
>
> This question likely has a 1 line answer, I'm just not seeing it. (2, 3, or
> 10 lines is fine too.)
>
> For a vector I can do group <- match(x, unqiue(x)) to get a vector that
> labels each element of x.
> What is an equivalent if x is a data frame?
>
In the past I've use apply with past to generate "group" identifiers:
x<-data.frame("X0"=c("A","B","C","C","D","A"), "X1"=c(1,2,1,1,3,1))
apply(x, 1, paste, collapse=".")
[1] "A.1" "B.2" "C.1" "C.1" "D.3" "A.1"
> The result does not have to be fast: the data set will have < 100 elements.
> Since this is inside the survival package, and that package is on the
> 'recommended' list, I can't depend on any package outside the recommended
> list.
David Winsemius
Alameda, CA, USA
'Any technology distinguishable from magic is insufficiently advanced.'
-Gehm's Corollary to Clarke's Third Law
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