I am not sure whether I could understand all things. Here is my code :
library(zoo)
# an reproducible example
SD <- 1
date1 <- seq(as.Date("2001-01-01"), as.Date("2002-12-1"), by = "day")
len1 <- length(date1)
set.seed(1) # to make it reproducible
data1 <- zoo(rnorm(len1), date1)
plot(data1)
# calculation for monthly or quarterly mean
calc = function(frequ = c("M S", "Q S"))
{
switch(frequ
"M S" = aggregate(data1, as.yearmon, mean)
"Q S" = aggregate(data1, as.yearqtr, mean))
}
However I am getting lot of errors while executing. Any further suggestion?
Regards,
On Sun, Jul 6, 2008 at 3:38 PM, <[EMAIL PROTECTED]> wrote:
> Why don't you try "switch" Let me assume that you want to calculate a=3 and
> b =5 by using one of "MEAN", "SUM","MIN", and "MAX functions. Then you could
> write your code: (If you want to calculate "MEAN")
>
> example<-function(fun=c("MEAN", "SUM", "MIN", "MAX")){
>>
> + fun<-match.arg(fun);a=3;b=5
> + switch( fun,
> + MEAN=(a+b)/2,
> + SUM=a+b,
> + MIN=min(a,b),
> + MAX=max(a,b))
> + }
>
>> example("MEAN")
>>
> [1] 4
>
>>
>> Hope this is helpful,
> Chunhao Tu
>
>
>
>
>
>
> Quoting Arun Kumar Saha <[EMAIL PROTECTED]>:
>
> There is "if-else" loop if I have to choose 1 item from a 2-item list.
>> However if I have a list of 4 items (let say) then how i can choose a
>> single
>> item without employing 'if-else' loop? I mean in VBA I can use
>> "select-case", is there any equivalent in R as well?
>>
>> Regards,
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>
>
>
[[alternative HTML version deleted]]
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