Hi

you does not need this:
dput(df1<-data.frame(col1=c(1,2,3,4,5),col2=c("aa","aa","bb","cc","dd")))

this is enough to represent exactly any object to mail:
> dput(df1)
structure(list(col1 = c(1, 2, 3, 4, 5), col2 = structure(c(1L,
1L, 2L, 3L, 4L), .Label = c("aa", "bb", "cc", "dd"), class = "factor")), .Names 
= c("col1",
"col2"), row.names = c(NA, -5L), class = "data.frame")

Anyway (I am sure there is better way but)
# make list from your data frames
lll<-list(df1, df2, df3)

#add new column to each part
for (i in 1:3) lll[[i]]$n<-i

#concatenate data to one data frame
dat<-do.call(rbind, lll)

# make table (and data frame from it)
data.frame(unclass(table(dat$col2, dat$n)))
   X1 X2 X3
aa  2  0  2
bb  1  3  0
cc  1  1  0
dd  1  0  0

I believe that in your dfn is typo in second row and first column and that with 
your 3 data.frames the result should be 1.

Cheers
Petr

> -----Original Message-----
> From: Ek Esawi [mailto:esaw...@gmail.com]
> Sent: Tuesday, February 27, 2018 2:54 PM
> To: PIKAL Petr <petr.pi...@precheza.cz>; r-help@r-project.org
> Subject: Re: [R] Aggregate over multiple and unequal column length data
> frames
>
> Thank you Pikal and Bert. My apology for posting parts of my previous email in
> HTML. Bert's suggestion will work but i am wondering if there is an 
> alternative
> especially in the case where the data frames are big; that is the difference 
> in
> lengths among them is large. Below is a list of sample date frames and desired
> result.
>
> EK
>
>
> dput(df1<-data.frame(col1=c(1,2,3,4,5),col2=c("aa","aa","bb","cc","dd")))
> dput(df2<-data.frame(col1=c(1,2,4,5),col2=c("bb","bb","cc","bb")))
> dput(df3<-data.frame(col1=c(1,3),col2=c("aa","aa")))
> # desired result
> dput(dfn<-data.frame(col1=c(2,2,1,1),col2=c(0,3,1,0),col3=c(2,0,0,0),row.names
> = c("aa","bb","cc","dd")))
>
> On Fri, Feb 23, 2018 at 7:45 AM, PIKAL Petr <petr.pi...@precheza.cz> wrote:
> > Hi
> >
> > Your example is rather confusing - partly because HTML formating, partly
> because weird coding.
> >
> > You probably could concatenate your data frames e.g. by rbind or merge and
> after that you could try to aggregate them somehow.
> >
> > I could construct example data.frames myself but most probably they would
> be different from yours and also the result would not be necessary the same as
> you expect.
> >
> > You should post those data frames as output from dput(data) and show us
> real desired result from those example data frames.
> >
> > Cheers
> > Petr
> >
> >> -----Original Message-----
> >> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ek
> >> Esawi
> >> Sent: Wednesday, February 21, 2018 3:34 AM
> >> To: r-help@r-project.org
> >> Subject: [R] Aggregate over multiple and unequal column length data
> >> frames
> >>
> >>  Hi All--
> >>
> >> I have generated several 2 column data frames with variable length.
> >> The data frames have the same column names and variable types. I was
> >> trying to aggregate over the 2nd column for all the date frames, but
> >> could not figure out how.
> >>
> >> I thought i could make them all of equal length then combine them in
> >> 1 data frame where i can use aggregate, the formula version Or to put
> >> them in a list and loop use lapply but did not know how to do that
> >> and thought there might be a simpler way.
> >>
> >> Below is an example of 3 data frames and the desired result; note
> >> that some levels don't appear in all and may be null over all
> >> variable, like the case of dd on the desired result which i would like to 
> >> list all
> levels even if some are all null.
> >>
> >> Thanks in advance,
> >>
> >> EK
> >>
> >>    df1           df2          df3
> >>
> >> c1 c2 c1 c2 c1 c2
> >> 1 aa 1 bb 1 aa
> >> 2 aa 2 bb 2 aa
> >> 3 bb 3 cc
> >> 4 cc 4 bb
> >> 5 bb
> >>
> >> desired result
> >>
> >> c1 c2 c2 c2
> >> aa 2 2
> >> bb 1 2 2
> >> cc 1 1
> >> dd
> >>
> >> [[alternative HTML version deleted]]
> >>

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