Hello,
Please always cc the list.
As for the question, yes, it does. If you want to remove just the ones
with exactly 73.1 use the pattern
grep("^73\\.1$", etc)
Explanation:
Beginning of string: ^
End of string: $
Escape special characters: \\ (needed because the period is a special
character.)
Hope this helps,
Rui Barradas
On 5/22/2018 12:50 PM, Ahmed Serag wrote:
Thank you Mr. Barradas. The code works great. Unfortunately I have also
some labeles with
173.1
273.1
the grep script remove them also ?
Any ideas Plz, Thanks again
************************
*Ahmed Serag*
/Analytical Chemistry Department/
/Faculty of Pharmacy/
/Al-Azhar University/
/Cairo/
/Egypt/
------------------------------------------------------------------------
*From:* Rui Barradas <ruipbarra...@sapo.pt>
*Sent:* Tuesday, May 22, 2018 1:34 PM
*To:* Ahmed Serag; r-help@r-project.org
*Subject:* Re: [R] remove rows of a matrix by part of its row name
Hello,
Use grep to get the row indices and then subset with a *negative* index
to remove those rows.
rn <- scan(what = character(), text = "
70/556
71.1/280
72.1/556
72.1/343
73.1/390
73.1/556
")
mat <- matrix(rnorm(6*6), nrow = 6)
row.names(mat) <- rn
inx <- grep("73\\.", row.names(mat))
new_mat <- mat[-inx, ]
new_mat
Hope this helps,
Rui Barradas
On 5/22/2018 11:48 AM, Ahmed Serag wrote:
Dear R-experts,
How can I remove a certain feature or observation by a part of its name. To be
clear, I have a matrix with 766 observations as a rows. The row names are like
this
70/556
71.1/280
72.1/556
72.1/343
73.1/390
73.1/556
Now I would like to remove all the rows that contain the text 73.1
Any ideas or suggestion please ?
Regards
**********************
Ahmed Serag
Analytical Chemistry Department
Faculty of Pharmacy
Al-Azhar University
Cairo
Egypt
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