Thank you Jeff. It is an excellent idea and i might try it out if
nothing works out. And i don't have 12 files on each sub directory;
EK
On Tue, Oct 9, 2018 at 11:30 AM Jeff Newmiller <jdnew...@dcn.davis.ca.us> wrote:
>
> Instead of changing the order in which you read the files, perhaps your
> analysis will work if you sort the data after you read it in. This may
> require that you add the month names as a column in the data frames, or you
> may already have dates in the data that you could sort by.
>
> One idea:
>
> fnames <- paste0( month.name, ".PDF" )
> resultdf <- do.call( rbind, lapply(fnames, function(fn) { read.csv(
> file.path( "datadir", fn ), as.is=TRUE ) } )
>
> but that only works if there are exactly 12 files. If there could be fewer,
> perhaps:
>
> fnames <- list.files( "datadir" )
> sfnames <- fnames[ match( sub("\\.PDF", "", fnames ), month.name ) ]
>
>
> On October 9, 2018 6:44:21 AM PDT, Ek Esawi <esaw...@gmail.com> wrote:
> >Hi All--
> >
> >I used base R list.file function to read files from a directory. The
> >file names are months (April, August, etc). That's the system reads
> >them in alphabetical order., but i want to reordered them in calendar
> >order (January, February, ...December).. I thought i might be able to
> >do it via RegEx or possibly gtools package, I am wondering if there is
> >an easier way.
> >
> >Thanks--EK
> >
> >Example
> >path = "C:/Users/name/Downloads/MyFiles"
> >file.names <- dir(path, pattern =".PDF")
> >
> >Example output
> >Output:
> >"February.PDF" "January.PDF" "March.PDF"
> >Desired output
> >"January.PDF" "February.PDF" "March.PDF"
> >
> >______________________________________________
> >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
> >https://stat.ethz.ch/mailman/listinfo/r-help
> >PLEASE do read the posting guide
> >http://www.R-project.org/posting-guide.html
> >and provide commented, minimal, self-contained, reproducible code.
>
> --
> Sent from my phone. Please excuse my brevity.
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