A partial dput is no help at all. A complete dput of part of your data is much
more likely to be helpful, but only if you see the same problem in it as you do
in the full data set.
As to private data... if you want data handling help in a public forum then you
need to create a small set of data that illustrates the problem. If you have to
manufacture the data by hand we don't care, but it is up to you to communicate
a clear question somehow.
On November 2, 2018 10:50:06 AM PDT, Ek Esawi <esaw...@gmail.com> wrote:
>Thank you Jeff and Bert. I know i have to use dput add provide a
>reproducible example. The problem is that the output,is huge, has many
>nested lists, and the info is private.
>
>Here is the first line of dput(FF) if it helps:
>dput(FF)
>list(list(list(structure(c("12/30 12/30", "01/02 01/02", "01/02 01/02",
>
>Thanks again--EK
>On Fri, Nov 2, 2018 at 11:21 AM Jeff Newmiller
><jdnew...@dcn.davis.ca.us> wrote:
>>
>> Can you supply the output of
>>
>> dput(FF)
>>
>> ?
>>
>> On November 2, 2018 8:00:08 AM PDT, Ek Esawi <esaw...@gmail.com>
>wrote:
>> >Hi All,
>> >
>> >I have a list that is made up of nested lists, as shown below. I
>want
>> >to remove all rows in each sub-list that start with an empty space,
>> >that’s the first entry of a row is blank; for example, on
>> >[[1]][[1]][[1]] Remove row 4,on [[1]][[1]][[3]] remove row 5, on
>> >[[1]][[2]][[1]] remove row 6, etc.. All rows start with 2 digits/ 2
>> >digits. My formula works on individual sublist but not the whole
>> >list.. I know my indexing is wrong, but don’t know how to fix it.
>> >
>> >
>> >> FF
>> >
>> >[[1]]
>> >[[1]][[1]]
>> >[[1]][[1]][[1]]
>> >[,1] [,2] [,3] [,4] [,5]
>> >[1,] "30/20" "AAAAAAAA" “ “ "-89"
>> >[2,] "02/20" "AAAAAAAA” “ “ "-98"
>> >[3,] "02/20" “AAAAAAA” “ “ "-84"
>> >[4,] “ “ “ “ “
>> >[[1]][[1]][[2]]
>> >[,1] [,2]
>> >[1,] "02/23" “AAAAAAAA” : 29" “
>> >[2,] "02/23" “AAAAAAAA” ." “
>> >[3,] "02/23" “AAAAAAAA” " “
>> >[4,] "02/23" “AAAAAAAA” "
>> >[[1]][[1]][[3]]
>> >[,1] [,2] [,3] [,4] [,5] [,6] [,7]
>> >[1,] "01/09" “AAAAAAAA" “ “ “ "53"
>> >[2,] "01/09" “AAAAAAAA” " “ “ “ "403"
>> >[3,] "01/09" “AAAAAAAA” " “ “ “ "83"
>> >[4,] "01/09" “AAAAAAAA” " “ “ “ "783"
>> >[5,] “ “ “AAAAAAAA” 3042742181" “ “ “ “
>> >[[1]][[2]]
>> >[[1]][[2]][[1]]
>> >[,1] [,2] [,3] [,4] [,5]
>> >[1,] “ “ “ “ “AAAAAAAA” "
>> >[2,] "Standard Purchases" “ “ “ "
>> >[3,] "24/90 "AAAAAAAA” “ "243" "
>> >[4,] "24/90 "AAAAAAAA” " "143" "
>> >[5,] "24/91 "AAAAAAAA” " “ "143" “
>> >[6,] “ “ “ “ "792"
>> >[[1]][[2]][[2]]
>> >[,1] [,2]
>> >[1,] "02/23" “AAAAAAAA”: 31" “
>> >[2,] "02/23" “AAAAAAAA”." “
>> >[3,] "02/23" “AAAAAAAA” " “
>> >[4,] "02/23" “AAAAAAAA”
>> >[5,] "02/23" “AAAAAAAA”
>> >[6,] "02/23" “AAAAAAAA” 20"
>> >[7,] "02/23" “AAAAAAAA” “
>> >[8,] "02/23" “AAAAAAAA” "33"
>> >[[1]][[3]]
>> >[[1]][[3]][[1]]
>> >[,1] [,2]
>> >[1,] "02/23" “AAAAAAAA”: 28" “
>> >[2,] "02/23" “AAAAAAAA”." “
>> >[3,] "02/23" “AAAAAAAA” " “
>> >[4,] "02/23" “AAAAAAAA” "
>> >[[1]][[3]][[2]]
>> >[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9]
>> >[1,] "02/23" “AAAAAAAA” " “ “ "53" "
>> >[2,] "02/24" “AAAAAAAA” " “ “ "
>> >[3,] “ “ “ “ “ “ “ “ "1,241"
>> >[4,] "02/24" "AAAAAAAA” “ "33”
>> >
>> >My Formula,:
>> >
>> >G <- lapply(FF, function(x) lapply(x, function (y) lapply(y,
>> >function(z) z[grepl("^[0-9][0-9]/",z[,1]),])))
>> >
>> >The error: Error in z[, 1] : incorrect number of dimensions
>> >
>> >
>> >
>> >Thanks in advance--EK
>> >
>> >______________________________________________
>> >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> >https://stat.ethz.ch/mailman/listinfo/r-help
>> >PLEASE do read the posting guide
>> >http://www.R-project.org/posting-guide.html
>> >and provide commented, minimal, self-contained, reproducible code.
>>
>> --
>> Sent from my phone. Please excuse my brevity.
--
Sent from my phone. Please excuse my brevity.
______________________________________________
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