On 21.02.19 20:43, Rui Barradas wrote:
Hello,
I don't understand the question.
Like this?
xx <- "B"
yy <- "D"
a[xx, on = v]
a[c(xx, yy), on = v]
Note that .(xx, yy) doesn't work. It outputs something else.
Could you give an example of more complicated expressions you have
doubts with?
Let's assume I'd like to create a subset like this, in data.frame syntax:
d[ (d[[v]] == a | d$b == "c") & d$c>2, ]
Here I have a column referenced by its name (stored in v), and compared
to a value stored in a, and the whole thing is part of a more complex
logical expression. I could write it in this conventional way, but I
wondered whether there is a better way that would leverage some of
data.tables syntax.
Pascal
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