Hi, I need help to extract data based on first column ID in R.
I used the below code but not succeed , it is not giving the row values, only showing the header of rows. > head(data) Root-1.S35.L001. Root-10.S75.L001 71f84e7910006f22684121564206e8ca 0.00000000 0 03b167b9f86f2519b4263b4125377eed 0.00000000 0 54e204fb99c80764e964456dadd6a0e5 0.00000000 0 55cd1fc570879d645bbf7a3642e9b0a8 0.00000000 0 65f5c31e12c277aec319e2096463f9d2 0.00000000 0 7bed62f0fef250fd831dcf13bf43f4fc 0.04679457 0 ..................................................... > head(otu.list) 9d94ce7d60e59034941e3a12bc37865e 1 8e60d301122d7aa359eb6b0b00f37f62 2 bfad6370d28182cc6304844e9bec7fb6 3 088571139af8e0a63fb6652df8a7438b 4 ccd70d57890f276a542ef4b5e5142d4c 5 cab4ca278af34bf722e0c7cb3219370b 6 72f30f3780145f16ac882eb8e2d189a5 .................................... > i <- data[[1]] %in% otu.list > dim(i) NULL > data[i, ] [1] Root-1.S35.L001 Root-10.S75.L001 Root-13.S5.L001 Root-14.S16.L001 [5] Root-17.S26.L001 Root-18.S36.L001 Root-19.S46.L001 Root-22.S56.L001 [9] Root-24.S66.L001 Root-25.S76.L001 Root-26.S6.L001 Root-27.S17.L001 [13] Root-3.S45.L001 Root-30.S27.L001 Root-32.S37.L001 Root-34.S47.L001 [17] Root-39.S57.L001 Root-4.S55.L001 Root-40.S67.L001 Root-41.S77.L001 [21] Root-43.S7.L001 Root-45.S18.L001 Root-47.S28.L001 Root-50.S38.L001 ............. Could you please suggest how I can get the row values along with the header? Thanks Yogesh [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.