Expectation: ifelse will use the same "repeat vectors to match the longest"
rule that other vectorised functions do.  So
a <- 1:5
b <- c(2,3)
ifelse(a < 3, 1, b)
=> ifelse(T T F F F <<5>>, 1 <<1>>, 2 3 <<2>>)
=> ifelse(T T F F F <<5>>, 1 1 1 1 1 <<5>>, 2 3 2 3 2 <<5>>)
=> 1 1 2 3 2
and that is indeed the answer you get.  Entirely predictable and consistent
with
other basic operations in R.

The only tricky thing I see is that R has
a strict vectorised  ifelse(logical.vector, some.vector, another.vector)
AND
a non-strict non-vectorised if (logical.scalar) some.value else
another.value
AND
a statement form if (logical.scalar) stmt.1; else stmt.2;


On Thu, 11 Jul 2019 at 01:47, Eric Berger <ericjber...@gmail.com> wrote:

> For example, can you predict what the following code will do?
> > a <- 1:5
> > b <- c(2,3)
> > ifelse( a < 3, 1, b)
>
>
> On Wed, Jul 10, 2019 at 4:34 PM José María Mateos <ch...@rinzewind.org>
> wrote:
>
> > On Wed, Jul 10, 2019, at 04:39, Eric Berger wrote:
> > > 1. The ifelse() command is a bit tricky in R. Avoiding it is often a
> good
> > > policy.
> >
> > You piqued my curiosity, can you elaborate a bit more on this?
> >
> > --
> > José María (Chema) Mateos || https://rinzewind.org
> >
> > ______________________________________________
> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> > http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
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