You're right. I was worried that c() would create a character vector and
deparse the unevaluated call in the process, but apparently it is an implicit
as.character _inside_ legend that is doing us in. (I can't offhand see where it
is happening, but there might be scope for improvement if legend() would just
accept a list object and treat the elements separately).
-pd
> On 20 Oct 2019, at 20:28 , Bert Gunter <bgunter.4...@gmail.com> wrote:
>
> However, note that:
>
> > class(c("Sans renard", bquote(.(densren) (ind./km)^2)))
> [1] "list" # by coercion
>
> so it does not seem necessary to explicitly call list(). That is:
>
> plot(1:100,1:100,type="n")
> legend(list(x=0,y=100), legend = as.expression(c("Sans renard",
> bquote(.(densren) (ind./km)^2))),lty=c(1,2),col=c("black","red"),bty="n")
>
> appears to suffice. I would appreciate correction if I'm wrong about this.
>
--
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Office: A 4.23
Email: pd....@cbs.dk Priv: pda...@gmail.com
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