Hi Ding,
If you are still having trouble, perhaps:
library(prettyR)
stretch_df(test1,"vntr1","val")
Jim
On Sat, Apr 4, 2020 at 5:58 AM Yuan Chun Ding <ycd...@coh.org> wrote:
>
> Hi R users,
>
> I want to do a data reshape from long to wide, I thought it was easy using
> tidyverse spread function, but it did not work well. Can you help me?
>
> Thank you,
>
> Ding
>
> test1 data frame is long file and test2 is the wide file I want to get
>
> test1 <- data.frame (vntr1=c("v1","v1", "v2","v2","v2","v2"),
> val =c(0.98,0.02, 0.59,0.12,0.11,0.04))
>
> test2 <- data.frame(vntr1=c("v1","v2"),
> a1 =c(0.98, 0.5693),
> a2 = c(0.02, 0.12),
> a3 =c(NA, 0.11),
> a4=c(NA, 0.04))
>
> the following code does not work
> test2 <-test1 %>%spread(vntr1, val)
>
> Error: Each row of output must be identified by a unique combination of keys.
> Keys are shared for 6 rows:
> * 1, 2
> * 3, 4, 5, 6
> Do you need to create unique ID with tibble::rowid_to_column()?
> Call `rlang::last_error()` to see a backtrace
>
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