Thank you so much!
On Fri, Apr 10, 2020 at 12:00 PM Rasmus Liland <jensras...@gmail.com> wrote:
>
> On 2020-04-10 11:15 -0500, Ana Marija wrote:
> > I have a data frame (tot) with about
> > 2000 columns. How can I extract from
> > it all strings that start with E14?
> >
> > I tried this:
> > e14 <- sapply(tot, function(x) grepl("^E14", x))
> >
> > but this returns me just TRUE and
> > FALSE vector, how do I get actual
> > strings that start with E14?
>
> Dear Ana,
>
> perhaps you thought of something along
> the lines of this:
>
> ncol <- 2000
> nrow <- 3
> line <-
> c("a", "b",
> "some text E14 bla bla some more text",
> "d",
> "E14 ... hey this starts and also ends with E14",
> "E14 something-something",
> "another string")
> tot <-
> as.data.frame(matrix(rep(line,
> times=ncol*nrow),
> ncol=ncol,
> byrow=T))
>
> # Now, tot is a df with some cells
> # containing replicates of line, some
> # cells there are now starting with E14
> # ... so we need to convert it to a
> # character matrix to be able to find
> # the indecies of the cells starting
> # with E14:
>
> tot <- as.matrix(tot)
> idx <- grepl("^E14", tot)
> tot[idx]
>
> Best,
> Rasmus
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
