Dear Jim, Eric, and Rui,
Great solutions! Thank you so much.
Best,
Milu
On Wed, Jul 15, 2020 at 9:20 AM Rui Barradas <ruipbarra...@sapo.pt> wrote:
> Hello,
>
> Yet another way, with package lubridate.
> When creating the "Date" objects, I set day = 1 to compare to TRUE below.
>
>
> library(lubridate)
>
> start <- as.Date(ISOdate(1861, 1, 1))
> end <- as.Date(ISOdate(2005, 12, 1))
>
> start + months(4139 - 2400)
> #[1] "2005-12-01"
>
> end == start + months(4139 - 2400)
> #[1] TRUE
>
>
> The argument to function months can be a vector of integers.
>
>
> start + months(1:(4139 - 2400))
>
>
>
> Then extract the months.
>
> month(start)
> month(end)
> month(start + months(<value>))
> month(start + months(4139 - 2400))
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 23:26 de 14/07/20, Miluji Sb escreveu:
> > Dear all,
> > I have a panel dataset with a large number of groups (200K+) with a
> > sequence representing the month of the observations (2400 - 4139). The
> data
> > is from January 1861 to December 2005.
> > My goal is to extract the corresponding month and year for each
> observation.
> >
> > I tried the following;
> > x$dt <- seq(from=as.Date("1861-01-01"),by='1 month',length=209000)
> >
> > However, the end date is clearly out of the range. I would like to
> convert
> > the month number (2400 - 4139) to January 1861 to December 2005 by ID.
> How
> > can I achieve this? Any help will be highly appreciated.
> >
> > Best,
> >
> > Milu
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
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> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
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