Hi John, df1<-sapply(df1,as.character)
Should do what you ask. The error message probably means that you should do this: df1<-df1[order(as.character(df1$year)),] as "year" is the name of the first column in df1, not a separate object. Jim On Tue, Nov 10, 2020 at 6:57 PM John <miao...@gmail.com> wrote: > Hi, > > I would like to sort the following simple dataframe by "year" > (characters), but the factor structure prevents me from doing so. How can I > remove the factor structure? Thanks! > > > df1 > year country > 4 2007 Asia; survey > 5 2010 8 countries in E/SE Asia > 6 2015 Ghana > 7 > 8 2000 US? > > str(df1) > 'data.frame': 5 obs. of 2 variables: > $ year : Factor w/ 9 levels "2017","2016",..: 4 5 3 6 7 > $ country: Factor w/ 9 levels "Euro Area\\newline Testing the MP > performance of the Euro Area",..: 4 5 6 7 8 > > df1[order(-year), ] > Error in order(-year) : object 'year' not found > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.