On Mon, 23 Aug 2021 08:37:54 +0200 Dr Eberhard Lisse <nos...@lisse.na> wrote:
> create the variables dynamically and add them to to > the grid (dynamically, ie adding more countries) In my opinion, creating variables in the global environment programmatically may lead to code that is hard to understand and debug [*]. A key-value data structure (a named list or a separate environment) would avoid the potential problems from variable name collision. How about the following: 1. Put the countries in a vector: c('Namibia', 'Germany', ...) 2. Use lapply() to get a list of objects returned from your PICTURE function 3. To save the pictures into individual files, loop over the list. You can use setNames on the step 1 or 2 to make it a named list and keep the country names together with their pictures: for (n in names(pictures)) { dev.new() print(pictures[[n]]) ggsave(paste0(n, '.png'), ...) dev.off() } (You can also use the png() device and plot straight to the file, avoiding the need to draw the plot in the window for a fraction of a second and for ggsave().) 4. Use the grobs= argument of grid.arrange() to pass the list of objects to arrange instead of passing individual objects via ... -- Best regards, Ivan [*] For example, there's this FAQ for a different language: https://perldoc.perl.org/perlfaq7#How-can-I-use-a-variable-as-a-variable-name? ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.