Data <- read.csv("./input/Source.csv", header=T)
v1 <- sort(unique(Data[, 1]))
cat(format(v1, justify = "right"), sep = "\n")
OK, working with the options you presented. This is the combination
where I gain the most benefit.
However, there is no listing of a column header with the output of this
syntax.
> cat(format(v1, justify = "right"), sep = "\n")
2
3
4
5
6
7
8
9
10
>
NOTE
The output here is correct (unique) based on the entries from the column.
QUESTION
How does one add a text label of something as simple as v1 to the
vertical output of this syntax, please?
*Stephen Dawson, DSL*
/Executive Strategy Consultant/
Business & Technology
+1 (865) 804-3454
http://www.shdawson.com <http://www.shdawson.com>
On 12/22/21 11:13 AM, Stephen H. Dawson, DSL via R-help wrote:
OK, now I get what you are suggesting.
Much appreciated.
Kindest Regards,
*Stephen Dawson, DSL*
/Executive Strategy Consultant/
Business & Technology
+1 (865) 804-3454
http://www.shdawson.com <http://www.shdawson.com>
On 12/22/21 11:08 AM, Duncan Murdoch wrote:
On 22/12/2021 10:55 a.m., Stephen H. Dawson, DSL wrote:
I see.
So, we are talking taking the output into a new dataframe. I was hoping
to have the output rendered on screen without another dataframe, but I
can live with this option it if must occur.
Am I correct the desired vertical output must first go to a dataframe?
No, that's just one option. The other 3 don't use dataframes.
Duncan Murdoch
*Stephen Dawson, DSL*
/Executive Strategy Consultant/
Business & Technology
+1 (865) 804-3454
http://www.shdawson.com <http://www.shdawson.com>
On 12/22/21 10:47 AM, Duncan Murdoch wrote:
On 22/12/2021 10:20 a.m., Stephen H. Dawson, DSL wrote:
Thanks for the reply.
Both syntax options work to render the correct (unique) output.
However,
the output is rendered as horizontal. What needs to happen to get the
output to render vertical, please?
The result of those expressions is a vector of the same type as the
column, so your question is really about how to get a vector to print
one element per line.
Probably the simplest way is to put the vector in a dataframe (or
matrix, or tibble, depending on which formatting you prefer). For
example,
v <- c("red", "green", "blue")
data.frame(v)
v
1 red
2 green
3 blue
If you want a more minimal display, try
cat(v, sep = "\n")
red
green
blue
or
cat(format(v, justify = "right"), sep = "\n")
red
green
blue
If you want this to happen when you auto-print the object, you can
give it a class attribute and write a function to print that class,
e.g.
class(v) <- "oneperline"
print.oneperline <- function(x, ...) cat(format(x, justify =
"right"), sep = "\n")
v
red
green
blue
Duncan Murdoch
*Stephen Dawson, DSL*
/Executive Strategy Consultant/
Business & Technology
+1 (865) 804-3454
http://www.shdawson.com <http://www.shdawson.com>
On 12/21/21 11:38 AM, Duncan Murdoch wrote:
On 21/12/2021 11:31 a.m., Duncan Murdoch wrote:
On 21/12/2021 11:20 a.m., Stephen H. Dawson, DSL wrote:
Thanks for the reply.
sort(unique(Data[1]))
Error in `[.data.frame`(x, order(x, na.last = na.last,
decreasing =
decreasing)) :
undefined columns selected
That's the wrong syntax: Data[1] is not "column one of Data". Use
Data[[1]] for that, so
sort(unique(Data[[1]]))
Actually, I'd probably recommend
sort(unique(Data[, 1]))
instead. This treats Data as a matrix rather than as a list.
Dataframes are lists that look like matrices, but to me the matrix
aspect is usually more intuitive.
Duncan Murdoch
I think Rui already pointed out the typo in the quoted text
below...
Duncan Murdoch
The recommended syntax did not work, as listed above.
What I want is the sort of distinct column output. Again, the
column
may
be text or numbers. This is a huge analysis effort with data
coming at
me from many different sources.
*Stephen Dawson, DSL*
/Executive Strategy Consultant/
Business & Technology
+1 (865) 804-3454
http://www.shdawson.com <http://www.shdawson.com>
On 12/21/21 11:07 AM, Duncan Murdoch wrote:
On 21/12/2021 10:16 a.m., Stephen H. Dawson, DSL via R-help
wrote:
Thanks everyone for the replies.
It is clear one either needs to write a function or put the
unique
entries into another dataframe.
It seems odd R cannot sort a list of unique column entries with
ease.
Python and SQL can do it with ease.
I've seen several responses that looked pretty simple. It's
hard to
beat sort(unique(x)), though there's a fair bit of confusion
about
what you actually want. Maybe you should post an example of the
code
you'd use in Python?
Duncan Murdoch
QUESTION
Is there a simpler means than other than the unique function to
capture
distinct column entries, then sort that list?
*Stephen Dawson, DSL*
/Executive Strategy Consultant/
Business & Technology
+1 (865) 804-3454
http://www.shdawson.com <http://www.shdawson.com>
On 12/20/21 5:53 PM, Rui Barradas wrote:
Hello,
Inline.
Às 21:18 de 20/12/21, Stephen H. Dawson, DSL via R-help
escreveu:
Thanks.
sort(unique(Data[[1]]))
This syntax provides row numbers, not column values.
This is not right.
The syntax Data[1] extracts a sub-data.frame, the syntax
Data[[1]]
extracts the column vector.
As for my previous answer, it was not addressing the
question, I
misinterpreted it as being a question on how to sort by numeric
order
when the data is not numeric. Here is a, hopefully, complete
answer.
Still with package stringr.
cols_to_sort <- 1:4
Data2 <- lapply(Data[cols_to_sort], \(x){
stringr::str_sort(unique(x), numeric = TRUE)
})
Or using Avi's suggestion of writing a function to do all the
work and
simplify the lapply loop later,
unisort2 <- function(vec, ...)
stringr::str_sort(unique(vec), ...)
Data2 <- lapply(Data[cols_to_sort], unisort, numeric = TRUE)
Hope this helps,
Rui Barradas
*Stephen Dawson, DSL*
/Executive Strategy Consultant/
Business & Technology
+1 (865) 804-3454
http://www.shdawson.com <http://www.shdawson.com>
On 12/20/21 11:58 AM, Stephen H. Dawson, DSL via R-help wrote:
Hi,
Running a simple syntax set to review entries in dataframe
columns.
Here is the working code.
Data <- read.csv("./input/Source.csv", header=T)
describe(Data)
summary(Data)
unique(Data[1])
unique(Data[2])
unique(Data[3])
unique(Data[4])
I would like to add sort the unique entries. The data in the
various
columns are not defined as numbers, but also text. I realize
1 and
10 will not sort properly, as the column is not defined as a
number,
but want to see what I have in the columns viewed as sorted.
QUESTION
What is the best process to sort unique output, please?
Thanks.
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______________________________________________
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see
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PLEASE do read the posting guide
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and provide commented, minimal, self-contained, reproducible
code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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