Hello,

If in each iteration i is a list, try removing the call to names().
Try, in the loop,


list2env(i, envir = .GlobalEnv)


The error message is telling that list2env's first argument must be a named list and names(i) is an unnamed vector, it's i that's the named list (you even changed its names in the previous instruction).

Hope this helps,

Rui Barradas

Às 18:38 de 03/10/2022, Kai Yang escreveu:
  Hi Rui,
list2env(file1, envir = .GlobalEnv) is worked very well. Thank you.

But when I tried to put the sample code  into for loop. I got error message:
for(i in filenames){
   assign(i, import_list(paste0(i, ".xlsx", sep="")))
   names(i) <- paste(i, names(i), sep = "_")
   list2env(names(i), envir = .GlobalEnv)
}
Error in list2env(names(i), envir = .GlobalEnv) :   first argument must be a 
named list

It seems I cannot put names(i) into for loop, Could you please help me to debug 
it?
Thank you,Kai    On Monday, October 3, 2022 at 10:14:25 AM PDT, Rui Barradas 
<ruipbarra...@sapo.pt> wrote:
Hello,


list2env(file1, envir = .GlobalEnv)


will create data.frames dx1, dx2, etc, in the global environment.
If you really need the names file1_dx1, file1_dx2, etc, you can first
change the names


names(file1) <- paste("file1", names(file1), sep = "_")


and then run list2env like above.

Hope this helps,

Rui Barradas

Às 16:51 de 03/10/2022, Kai Yang via R-help escreveu:
Hi R team,
I can use rio package to read excel file into R as a list. The excel file 
content multiple sheets (30 - 40 data sheets). I can convert each data elements 
into dataframe manually. I have multiple excel files with multiple data sheets. 
I need to load them into R and do the comparison for same sheet name from 
difference excel file. My current code is:
   library(rio)   setwd ("C:/temp")
filenames <- gsub("\\.xlsx$","", list.files(pattern="\\.xlsx$"))
for(i in filenames){
     assign(i, import_list(paste0(i, ".xlsx", sep="")))
}
file1_dx1     <-  file1[["dx1"]]

file1_dx2     <-  file1[["dx2"]]

file1_dx3     <-  file1[["dx3"]]

file2_dx1     <-  file1[["dx1"]]

file2_dx2     <-  file1[["dx2"]]
......

I hope the code can automatic converting the list (may have 30 - 40 lists) by 
adding file name (such as: filename_sheetname) and put it in for loop


Thank you,
Kai




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