Dear members,
I have the following code:
> TB <- {x <- 3;y <- 5}
> TB
[1] 5
It is consistent with the documentation: For {, the result of the last
expression evaluated. This has the visibility of the last evaluation.
But both x AND y are created, but the "return value" is y. How can this be
advantageous for solving practical problems? Specifically, consider the
following code:
F <- function(X) { expr; expr2; { expr5; expr7}; expr8;expr10}
Both expr5 and expr7 are created, and are accessible by the code outside of the
nested braces right? But the "return value" of the nested braces is expr7. So
doesn't this mean that only expr7 should be accessible? Please help me entangle
this (of course the return value of F is expr10, and all the other objects
created by the preceding expressions are deleted. But expr5 is not, after the
control passes outside of the nested braces!)
Thanking you,
Yours sincerely,
AKSHAY M KULKARNI
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