Yes. Any of the following worked. The pipe greater than (|>) is neat!
Thanks.
> v<-goprobit.p$est
> names(v) |> grep("somewhat|very", x = _)
[1] 6 7 8 9 10 11 12 13 28 29 30 31 32 33 34 35 50 51 52 53 54 55
56 57
> v |> names() |> grep("somewhat|very", x = _)
[1] 6 7 8 9 10 11 12 13 28 29 30 31 32 33 34 35 50 51 52 53 54 55
56 57
> which(grepl("very|somewhat",names(v)))
[1] 6 7 8 9 10 11 12 13 28 29 30 31 32 33 34 35 50 51 52 53 54 55
56 57
> jj<-grep("very|somewhat",names(v)); jj
[1] 6 7 8 9 10 11 12 13 28 29 30 31 32 33 34 35 50 51 52 53 54 55
56 57
>
On 7/13/2024 12:31 AM, Rui Barradas wrote:
Hello,
So any of
names(goprobit.p$est) |> grep("somewhat|very", x = _)
goprobit.p$est |> names() |> grep("somewhat|very", x = _)
should work, right?
Hope this helps,
Rui Barradas
Às 16:57 de 12/07/2024, Steven Yen escreveu:
Thanks. First and second of the following worked, but the third (with
coef) did not. This may be because I programmed my own estimation
program. In short,
names(goprobit.p$est) was recognized, but
names(coef(goprobit)) was not
> which(grepl("very|somewhat",names(goprobit.p$est)))
[1] 6 7 8 9 10 11 12 13 28 29 30 31 32 33 34 35 50 51 52 53 54
55 56 57
> jj<-grep("very|somewhat",names(goprobit.p$est)); length(jj)
[1] 24
> jj<-grep("very|somewhat",names(coef(goprobit))); length(jj)
Error: object 'goprobit' not found
On 7/12/2024 11:23 PM, Rui Barradas wrote:
Hello,l
Though the question is already answered, here is another answer to
what is 'x'.
The output in the OP is not a lm or glm output but if your
regression model was programmed according to recommended practices,
there must be a 'coefficients' member in the list or object it
returns and the following should work.
# this is 'x', a named character vector
coef(fit)
#
fit |> coef() |> names() |> grep("somewhat|very", x = _)
Hope this helps,
Rui Barradas
Às 10:26 de 12/07/2024, Steven Yen escreveu:
Thanks. In this case below, what is "x"? I tried rownames(out)
which did not work.
Sorry. Does this sound like homework to you?
On 7/12/2024 5:09 PM, Uwe Ligges wrote:
On 12.07.2024 10:54, Steven Yen wrote:
Below is part a regression printout. How can I use "grep" to
identify
rows headed by variables (first column) with a certain label. In
this
case, I like to find variables containing "somewhath",
"veryh", "somewhatm", "verym", "somewhatc", "veryc","somewhatl",
"veryl". The result should be an index 6:13 or
6,7,8,9,10,11,12,13. Note
that they all contain "somewhat" and "very". Thanks.
Sounds like homework?
which(grep("very|somewhat", x))
Best,
Uwe Ligges
est se t p g sig x.1.age 0.0341 0.0138 2.4766 0.0133 -3.8835e-04 **
x.1.sleep -0.1108 0.0059 -18.6277 0.0000 -4.4572e-04 *** x.1.primary
-0.0694 0.0289 -2.4002 0.0164 -9.9638e-06 ** x.1.middle -0.2909
0.0356
-8.1657 0.0000 -1.4913e-05 *** x.1.high -0.4267 0.0463 -9.2118
0.0000
-3.6246e-05 *** x.1.somewhath -0.6188 0.0256 -24.1971 0.0000
-3.1337e-05
*** x.1.veryh -0.7580 0.0331 -22.8695 0.0000 -2.9558e-05 ***
x.1.somewhatm -0.3413 0.0426 -8.0112 0.0000 -1.8920e-05 ***
x.1.verym
-0.3813 0.0446 -8.5413 0.0000 -4.4029e-05 *** x.1.somewhatc -0.3101
0.0649 -4.7783 0.0000 -1.4353e-05 *** x.1.veryc -0.2977 0.0648
-4.5910
0.0000 -4.8986e-05 *** x.1.somewhatl -0.6310 0.0424 -14.8846 0.0000
-1.9543e-05 *** x.1.veryl -0.9132 0.0462 -19.7525 0.0000
-4.4603e-05 ***
...
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and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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