This can be done analytically: after changing a variable (2*t -> t) and some scaling we need to compute f(x) = integral from 0 to 20 of (t^x*exp(-t))dt/factorial(x)
f(0) = int from 0 to 20 of exp(-t)dt = 1 - exp(-20) and integration by parts yields (for x=1,2,3,...) f(x) = -exp(-20)*20^x/factorial(x) + f(x-1) so that f(x) = 1 - exp(-20)*sum(20^k/factorial(k)) where the sum is for k=0,1,...,x If I did not a mistake, your original quantity should be f(x)/20. --- On Thu, 28/8/08, jose romero <[EMAIL PROTECTED]> wrote: > From: jose romero <[EMAIL PROTECTED]> > Subject: [R] Integrate a 1-variable function with 1 parameter (Jose L. Romero) > To: r-help@r-project.org > Received: Thursday, 28 August, 2008, 12:23 AM > Hey fellas: > > I would like to integrate the following function: > > integrand <- function (x,t) { > exp(-2*t)*(2*t)^x/(10*factorial(x)) > } > > with respect to the t variable, from 0 to 10. > The variable x here works as a parameter: I would like to > integrate the said function for each value of x in > 0,1,..,44. > > I have tried Vectorize to no avail. > > Thanks in advance, > jose romero > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.