Hi R users, I have a question which is some what related to this thread.
Here is the setup:
z is a list of lists, with no names.
zz is same is z, but with names.
with names on zz, I can crawl on the data with lapply, but I don't know how do
the same on z (without names). Can someone help?
### === here is the code, which explains more clear of my problem
x <- list(1:3,4:6)
y <- list(11:13,14:16)
z <- list(x,y)
xx <- x
names(xx) <- c("1","2")
yy <- y
names(yy) <- c("1","2")
zz <- list(xx,yy)
lapply(zz, "[[", "1")
lapply(zz, "[[", "2")
# Question: how can I get the same thing from z?
# i.e. lapply(z, "[[", <???>), what is <???> so that
# I can get the same values as lapply(zz, "[[", "1").
# I tried <???>=[[1]], <???>=[1], <???>="[[". They all don't work.
# I feel that I need a string or something to tell lapply what I want.
This is a simplify version of my problem; in my case, I can't name all the
sub-lists, please help.
Thanks in advance,
Gary
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Peter Dalgaard
Sent: Tuesday, August 26, 2008 6:27 PM
To: jim holtman
Cc: r-help@r-project.org
Subject: Re: [R] loop with splitted data
jim holtman wrote:
> Is this what you want:
>
>
>> y = c(rep(2,5),rep(3,5))
>> ma <- data.frame(x = 1:10, y=y )
>> splitted <- split(ma, ma$y)
>> for (counter in (min(ma$y):max(ma$y)))
>>
> + {
> + cat(counter, ":", splitted[[as.character(counter)]]$x, '\n')
> + }
> 2 : 1 2 3 4 5
> 3 : 6 7 8 9 10
>
>
But maybe this is what he really wanted:
> lapply(splitted,"[[", "x")
$`2`
[1] 1 2 3 4 5
$`3`
[1] 6 7 8 9 10
or even
> split(ma$x, ma$y)
$`2`
[1] 1 2 3 4 5
$`3`
[1] 6 7 8 9 10
--
O__ ---- Peter Dalgaard Øster Farimagsgade 5, Entr.B
c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907
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