Dear Jesse, You can use a "list" to do what you want: # Data mylist1=list(x=1:5,y=rnorm(10),z=letters[1:15]) mylist2=list(x=1:15,y=rnorm(5),z=letters[1:5])
# Length of each object in mylist1 l1=sapply(mylist1,length) # The same for mylist2 l2=sapply(mylist2,length) # Ratio l1/l2 x y z 0.3333333 2.0000000 3.0000000 Now, if you have different matrices, something like this should do the job: # Data m1=matrix(rnorm(200),ncol=20) m2=matrix(rnorm(100),ncol=20) # Length of each column lm1=apply(m1,2,length) lm2=apply(m2,2,length) # Ratio lm1/lm2 HTH, Jorge On Tue, Sep 16, 2008 at 3:48 PM, j daniel <[EMAIL PROTECTED]> wrote: > > Greetings, > > I need to compare the ratios of vector sizes like this: > > length(object1) / length(object2) > > I have many vector objects to compare, so I would like to do it in a loop. > I created a loop like this: > > > mat1 <- matrix() > > for (i in 1:6) > { > for (j in 1:6) > { > > mat1[i,j] <- length( paste("object",i,sep="")) / > (paste("object",j,sep="") ) > > } > } > > > The loop does not work, however, because paste("object",i,sep="") > creates > a character vector of length 1. Is there a way to cast this as an object > so > that it can be evaluated in the loop? > > Thanks in advance > > Jesse > -- > View this message in context: > http://www.nabble.com/casting-a-character-vector-as-an-object-tp19519216p19519216.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.