Hi Eric, > data<-list(x1 <- c(0,1,2,3),x2 <- c(7,8),x3 <- c(2,6,6,8), x4 <- c(4,8)) > lapply(X=data, mean) [[1]] [1] 1.5
[[2]] [1] 7.5 [[3]] [1] 5.5 [[4]] [1] 6 Hope it helps Chunhao eric lee-8 wrote: > > Hi. I have a list where each object in the list has multiple parts. I'd > like to take the mean of just one part of each object. Is it possible to > do > this with lapply? If not, can you recommend another function? Thanks. > > eric > >> x1 <- c(0,1,2,3) >> x2 <- c(7,8) >> x3 <- c(2,6,6,8) >> x4 <- c(4,8) >> >> Lst1 <- list(label1 = x1,label2 = x2) >> Lst2 <- list(label1 = x3, label2 = x4) >> >> BigList <- list(Lst1, Lst2) >> >> lapply(BigList$label1, mean) > list() >> > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://www.nabble.com/lapply-where-each-list-object-has-multiple-parts-tp19772755p19772797.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
