Unfortunately, I have the same error message. lapply(rowsplit, function(x)mean(x[,sapply(x, is.numeric)])) works but not with median. Strange, isn't it?
Any other idea? Thanks in advance, Ptit Bleu. Henrique Dallazuanna wrote: > > Try this: > > lapply(l, function(x)median(x[,sapply(x, is.numeric)])) > > > -- > Henrique Dallazuanna > Curitiba-Paraná-Brasil > 25° 25' 40" S 49° 16' 22" O > > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://www.nabble.com/sapply-and-median%2C-possible-or-not---tp20378222p20378663.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
