Thanks to everyone who responded. This turns out to be amazingly easy.
To count characters including spaces:
nchar(x)
To count characters excluding spaces:
nchar(gsub(" *","",x))
Thanks!
On Fri, Dec 12, 2008 at 11:00 AM, Petr PIKAL <petr.pi...@precheza.cz> wrote:
> Hi
>
>
> r-help-boun...@r-project.org napsal dne 12.12.2008 16:31:10:
>
>> Dear list,
>> I have a variable that consists of typed responses. I wish to compute
>> a variable equal to the number of characters in the original variable.
>> For example:
>>
>> > x <- c("convert this to 32 because it has 32 characters", "this one
> has 22
>> characters", "12 characters")
>>
>> [Some magic function here]
>
> If you consider space as a character then
>
> nchar(x)
>
> gives you the result.
>
> If not so such construction can do it
>
> unlist(lapply(lapply(strsplit(x, " "), paste, collapse=""), nchar))
>
> Regards
> Petr
>
>>
>> > x
>> [1] 32 22 12
>>
>> Any ideas?
>>
>> ______________________________________________
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>> PLEASE do read the posting guide
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>> and provide commented, minimal, self-contained, reproducible code.
>
>
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