Try this: > dateseq <- function(i) seq(DF[i, 1], DF[i, 2], 1) > table(as.Date(unlist(lapply(1:nrow(DF), dateseq)), origin = "1970-01-01"))
2009-01-01 2009-01-02 2009-01-03 2009-01-04 2009-01-05 2009-01-06 2009-01-07 1 2 3 3 2 1 1 2009-01-08 2009-01-09 1 1 On Mon, Feb 9, 2009 at 10:57 AM, <stefan.peters...@inizio.se> wrote: > > hi, > > I have some session data in a dataframe, where each session is recorded with > a start and a stop date. Like this: > > session_start session_stop > =================== > 2009-01-03 2009-01-04 > 2009-01-01 2009-01-05 > 2009-01-02 2009-01-09 > > A session is at least one day long. Now I want a dataframe with 'active > sessions' per date. Like this: > > date active_sessions > ============= > 2009-01-01 1 > 2009-01-02 2 > 2009-01-03 3 > 2009-01-04 3 > 2009-01-05 2 > 2009-01-06 1 > 2009-01-07 1 > 2009-01-08 1 > 2009-01-09 1 > > How do I do that? I've searched the usual sources, but my newbie status and > language barrier left me with nothing. So plz, anyone? > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.