Hi Gundala: Below works but I was trying to figure out a way to not have
to add the last line and I gave up.
dat<-c(0.00377467,0.00377467,0.00377467,0.00380083,0.00380083,0.00380083,0.00380959,
0.00380959,0.00380959,0.00380083,0.00380083,0.00380083)
# MAKE A TEMPORARY MATRIX
temp <- matrix(dat,nrow=3)
# RBIND THE ZEROS AND MAKE IT A VECTOR
withzeros <- as.vector(rbind(temp,0))
# TAKE THE LAST ONE OFF
withzeros<-head(withzeros,-1)
On Thu, Feb 19, 2009 at 1:47 AM, Gundala Viswanath wrote:
Hi,
I have a vector that look like this:
dat
V1 V2 V3 V4 V5 V6
0.00377467 0.00377467 0.00377467 0.00380083 0.00380083 0.00380083
V7 V8 V9 V10 V11 V12
0.00380959 0.00380959 0.00380959 0.00380083 0.00380083 0.00380083
what I want to do is to insert 0 (zero) for every 3 position yielding:
V1 V2 V3 V4 V5 V6
V7 V8
0 0.00377467 0.00377467 0.00377467 0 0.00380083 0.00380083
0.00380083
V9 V10 V11 V12 V13 V14
V15 V16
0 0.00380959 0.00380959 0.00380959 0 .00380083 0.00380083 0.00380083
Is there a quick way to do it in R?
- Gundala Viswanath
Jakarta - Indonesia
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and provide commented, minimal, self-contained, reproducible code.
