Hi guRus, My discipline (experimental psychology) is gradually moving away from Null Hypothesis Testing and towards measures of evidence. One measure of evidence that has been popular of late is the likelihood ratio. Glover & Dixon (2005) demonstrate the calculation of the likelihood ratio from ANOVA tables, but I'm also interested in non-parametric statistics and wonder if anyone has any ideas on how to compute a likelihood ratio from a randomization test (aka. permutation test)?
Say one had two groups and were interested in whether the mean scores of the two groups differ in a manner consistent with random chance or in a manner consistent with a non-null effect of some manipulation applied to the two groups. The randomization test addresses this by randomly re-assigning the participants to the groups, re-computing the difference between means, and repeating many times, yielding a distribution of simulated difference scores that represents the distribution expected by chance. Within a Null Hypothesis Testing framework you then estimate the probability of the null by observing the proportion of simulated difference scores that are greater in magnitude than the observed difference score. Any guesses on how to translate this into a quantification of evidence? Mike -- Mike Lawrence Graduate Student Department of Psychology Dalhousie University Looking to arrange a meeting? Check my public calendar: http://tinyurl.com/mikes-public-calendar ~ Certainty is folly... I think. ~ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.