One can't assume an arbitrary function necessarily works with zoo
objects although many do; however, for functions that are sufficiently
similar to lm, like lmrob, dyn in the dyn package can transform it to
work with zoo (as well as with ts and a number of other time series
classes). Just preface lmrob with dyn$ like this:

library(dyn)
mod1<-dyn$lmrob(as.zooreg(dad)~seq(58))
summary(mod1)

On Thu, Mar 12, 2009 at 6:13 AM, Víctor Homar <victor.ho...@uib.cat> wrote:
> Hi all and thanks for your time in advance,
>
> I can't figure out why summary.lmrob complains when lmrob is used on a
> zooreg object. If the zooreg object is converted to vector before
> calling lmrob, no problems appear.
>
> Let me clarify this with an example:
>
>>library(robustbase)
>>library(zoo)
>>dad<-c(801.4625,527.2062,545.2250,608.2313,633.8875,575.9500,797.0500,706.4188,
> 816.7000,619.1187,430.6188,852.1750,574.9937,528.1250,376.6187,507.7437,
> 443.0813,463.6250,716.1063,529.1250,705.7437,959.2937,653.0187,717.4438,
> 644.3125,718.1000,620.5187,759.3312,712.9750,606.6688,451.9250,560.2313,
> 308.1875,551.7687,615.3312,673.1250,678.4562,485.5312,491.8875,568.5688,
> 689.5750,507.0875,467.9125,539.4875,461.8625,827.3750,507.9250,526.5688,
> 363.9625,355.8813,585.9750,792.8438,698.6250,625.1063,463.4875,619.4688,
> 684.9438,815.3438)
>
>> mod1<-lmrob(dad~seq(58))
>> summary(mod1)
>
> Call:
> lmrob(formula = dad ~ seq(58))
>
> Weighted Residuals:
>     Min       1Q   Median       3Q      Max
> -291.106  -98.083    0.912  102.219  349.697
>
> Coefficients:
>            Estimate Std. Error t value Pr(>|t|)
> (Intercept) 630.2021    38.5583  16.344   <2e-16 ***
> seq(58)      -0.9366     1.1639  -0.805    0.424
> ---
> Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
>
> Robust residual standard error: 147.3
> Convergence in 8 IRWLS iterations
>
> Robustness weights:
>  4 weights are ~= 1. The remaining 54 ones are summarized as
>   Min. 1st Qu.  Median    Mean 3rd Qu.    Max.
>  0.5522  0.8858  0.9537  0.9212  0.9831  0.9990
> Algorithmic parameters:
> tuning.chi         bb tuning.psi refine.tol    rel.tol
>  1.5476400  0.5000000  4.6850610  0.0000001  0.0000001
>  nResample     max.it     groups    n.group   best.r.s   k.fast.s
> k.max
>       500         50          5        400          2          1
> 200
>  trace.lev compute.rd
>         0          0
> seed : int(0)
>>
>> mod1<-lmrob(as.zooreg(dad)~seq(58))
>> summary(mod1)
>
> Call:
> lmrob(formula = as.zooreg(dad) ~ seq(58))
>
> Weighted Residuals:
> Error in if (xi == xj) 0L else if (xi > xj) 1L else -1L :
>  argument is of length zero
>
>
>
>
> My problem is I typically work with zooreg objects and summary.lmrob
> complains unless I convert them to vector in the lmrob call. Any idea
> what is going wrong?
>
>
> Thanks a lot,
>
> Víctor.
>
> --
> --------------------------------------------------------------------
> Víctor Homar Santaner
> Grup de Meteorologia
>
> Edif. Mateu Orfila                      Tel: +34 971 17 1376
> Universitat de les Illes Balears        Fax: +34 971 17 3426
> 07122 Palma de Mallorca (SPAIN)         Email: victor.ho...@uib.es
>
>                Knowledge is contagious. Infect truth.
> --------------------------------------------------------------------
>
>
>        [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to