Hi,
This is a bug I think. [.data.frame treats its arguments differently
depending on the number of arguments.
> d <- data.frame(x = rnorm(5), y = rnorm(5), z = rnorm(5) )
> d[, 1:2]
x y
1 0.45141341 0.03943654
2 -0.87954548 1.83690210
3 -0.91083710 0.22758584
4 0.06924279 1.26799176
5 -0.20477052 -0.25873225
> base:::`[.data.frame`( d, j=1:2)
x y z
1 0.45141341 0.03943654 -0.8971957
2 -0.87954548 1.83690210 0.9083281
3 -0.91083710 0.22758584 -0.3104906
4 0.06924279 1.26799176 1.2625699
5 -0.20477052 -0.25873225 0.5228342
but also:
> d[ j=1:2]
x y z
1 0.45141341 0.03943654 -0.8971957
2 -0.87954548 1.83690210 0.9083281
3 -0.91083710 0.22758584 -0.3104906
4 0.06924279 1.26799176 1.2625699
5 -0.20477052 -0.25873225 0.5228342
`[.data.frame` only is called with two arguments in the second case, so
the following condition is true:
if(Narg < 3L) { # list-like indexing or matrix indexing
And then, the function assumes the argument it has been passed is i, and
eventually calls NextMethod("[") which I think calls
`[.listof`(x,i,...), since i is missing in `[.data.frame` it is not
passed to `[.listof`, so you have something equivalent to as.list(d)[].
I think we can replace the condition with this one:
if(Narg < 3L && !has.j) { # list-like indexing or matrix indexing
or this:
if(Narg < 3L) { # list-like indexing or matrix indexing
if(has.j) i <- j
> `[.data.frame`(d, j=1:2)
x y
1 0.45141341 0.03943654
2 -0.87954548 1.83690210
3 -0.91083710 0.22758584
4 0.06924279 1.26799176
5 -0.20477052 -0.25873225
However, we would still have this, which is expected (same as d[1:2] ):
> `[.data.frame`(d, i=1:2)
x y
1 0.45141341 0.03943654
2 -0.87954548 1.83690210
3 -0.91083710 0.22758584
4 0.06924279 1.26799176
5 -0.20477052 -0.25873225
Romain
baptiste auguie wrote:
Dear all,
Trying to extract a few rows for each element of a list of
data.frames, I'm puzzled by the following behaviour,
d <- lapply(1:4, function(i) data.frame(x=rnorm(5), y=rnorm(5)))
str(d)
lapply(d, "[", i= c(1)) # fine, this extracts the first columns
lapply(d, "[", j= c(1, 3)) # doesn't do nothing ?!
library(plyr)
llply(d, "[", j= c(1, 3)) # same
Am i misinterpreting the meaning of "j", which I thought was an
argument of the method "[.data.frame"?
args(`[.data.frame`)
function (x, i, j, drop = if (missing(i)) TRUE else length(cols) ==
1)
Many thanks,
baptiste
_____________________________
Baptiste Auguié
School of Physics
University of Exeter
Stocker Road,
Exeter, Devon,
EX4 4QL, UK
Phone: +44 1392 264187
http://newton.ex.ac.uk/research/emag
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PLEASE do read the posting guide
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--
Romain Francois
Independent R Consultant
+33(0) 6 28 91 30 30
http://romainfrancois.blog.free.fr
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
