I do not think that the form [[1:3]] is legit.
> ltest <- list( "a", "b", "c", "d")
> ltest[[1:3]]
Error in ltest[[1:3]] : recursive indexing failed at level 2
You might try with single brackets:
> ltest[1:3]
[[1]]
[1] "a"
[[2]]
[1] "b"
[[3]]
[1] "c"
--
David Winsemius
On Apr 3, 2009, at 2:45 PM, <rkevinbur...@charter.net> wrote:
I have a list of data.frames
str(bins)
List of 19217
$ 100026:'data.frame': 1 obs. of 6 variables:
..$ Sku : chr "100026"
..$ Bin : chr "T149C"
..$ Count: int 108
..$ X : int 20
..$ Y : int 149
..$ Z : chr "3"
$ 100030:'data.frame': 1 obs. of 6 variables:
.......
As you can see one 'column' is "Count". This list seems to contain
19217 data.frames. I would like to create an array of 19217 integers
which hold the values of the "Count" column. I have tried the
obvious (to me):
bins[[1:3]]$Count
But that returns NULL instead of an array of length 3 that I was
expecting. Interestingly bins[[1]]$Count returns the first "Count"
in the list of data frames. How do I get all of the "Count"s?
Thank you.
Kevin
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