Hi Torsten,
If you are fitting a line, why are you using "loess"? Why not simply
use "lm" to fit a regression line that goes through the origin? (i.e.
with no intercept).
Julian
jimm-pa...@gmx.de wrote:
Hi all,
I'm fitting a line to my dataset. Later I want to predict missing values that exceed the
[min,max] interval of my empirical data, therefore I choose surface="direct"
for extrapolation.
l1<-loess(y1~x1,span=0.1,data.frame(x=x1,y=y1),control=loess.control(surface="direct"))
In my application it is highly important that the fitted line intercepts at the
point of origin. Is it possible to do this in R?
Thanks in advance.
Cheers,
Torsten
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