Thank you, it is working.

David

2009/4/23 Henrique Dallazuanna <www...@gmail.com>

> Try this:
>
> lapply(names(col.prop), function(idx)rbind(col.prop[[idx]], n[[idx]]))
>
> On Thu, Apr 23, 2009 at 7:33 AM, David Hajage <dhajag...@gmail.com> wrote:
>
>> I have two lists (and possibly more):
>>
>> col.prop <-
>> structure(list(B = structure(c(0.5, 0.5, 0.6, 0.4, 0.555555555555556,
>> 0.444444444444444), class = c("cast_matrix", "matrix"), .Dim = 2:3,
>> .Dimnames = list(
>>    NULL, NULL)), D = structure(c(1, 0, 0.666666666666667,
>> 0.333333333333333,
>> 0.8, 0.2), class = c("cast_matrix", "matrix"), .Dim = 2:3, .Dimnames =
>> list(
>>    NULL, NULL))), .Names = c("B", "D"))
>> n <-
>> structure(list(B = c(4, 5, 9), D = c(4, 6, 10)), .Names = c("B",
>> "D"))
>>
>> > col.prop
>> $B
>>     [,1] [,2]      [,3]
>> [1,]  0.5  0.6 0.5555556
>> [2,]  0.5  0.4 0.4444444
>>
>> $D
>>     [,1]      [,2] [,3]
>> [1,]    1 0.6666667  0.8
>> [2,]    0 0.3333333  0.2
>>
>> > n
>> $B
>> [1] 4 5 9
>>
>> $D
>> [1]  4  6 10
>>
>> I would like to "rbind" each element with the corresponding element of
>> each
>> list ($B with $B and $D with $D):
>>
>> > res
>> $B
>>     [,1] [,2]      [,3]
>> [1,]  0.5  0.6 0.5555556
>> [2,]  0.5  0.4 0.4444444
>> [3,]    4    5         9
>>
>> $D
>>     [,1]      [,2] [,3]
>> [1,]    1 0.6666667  0.8
>> [2,]    0 0.3333333  0.2
>> [3,]    4         6   10
>>
>> I've made an ugly loop to do this... Is there an easier way?
>>
>> Thank you very much.
>>
>> David
>>
>>        [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>

        [[alternative HTML version deleted]]

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