Hi: Here is simplified example of what I am having trouble with: I want to set the gray shade of the background of each panel of a xyplot with its mean. My aim is to be able to compare at a glance which panel has the highest mean. But, in order to achieve this I have to normalize the means between 0 and 1. The normalization is necessary to stay within the valid range for the gray() command. I can’t figure out how to do it :-(
Here is an example where I use max(Oats$yield) (the all around maximum value) to normalize. Note that what I am looking for is an expression what would mean something like this as max(<mean of every panel>) # Start Example, just copy and paste data(Oats, package = "MEMSS") tp1.oats <- xyplot(yield ~ nitro | Variety + Block, data = Oats, panel = function(x, y, subscripts, ...) { # How to normalize my heatmap metric with # the value of the panel that has maximum average ? # metric = eval(mean(y)/ max(<mean-of-each-panel>))))) metric = eval(mean(y)/max(Oats$yield)) panel.fill(col = gray(metric)) panel.lines(x,y) } ) print(tp1.oats) # End Example Does anybody have any suggestion how I can get max(<mean-of-each-panel>) ? Thanks PS: Deepayan THANKS to your reply to my previous email it was exactly what I needed. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.