Romain Francois wrote: > > Hi, > > Something like this perhaps: > > files <- dir( pattern = "\\.csv$" ) > for( x in files){ > assign( sub( "\\.csv$", "", x ) , read.csv(x), envir = .GlobalEnv ) > }
or maybe csvs = Map(read.csv, dir(pattern='\\.csv$')) possibly with a correction of list item names names(csvs) = sub('\\.csv$', '', names(csvs)) which is optional, since the content of foo.csv can be accessed as csvs$foo (or as csvs[['foo', exact=FALSE]]) instead of csvs$foo.cvs even without such a correction. vQ > > Romain > > Mark Na wrote: >> Hi R-helpers, >> >> I would like to read into R all the .csv files that are in my working >> directory, without having to use a read.csv statement for each file. >> >> Each .csv would be read into a separate dataframe which would acquire >> the filename of the .csv. >> >> As an example: >> >> Mark<-read.csv("Mark.csv") >> >> ...but the code (or command) would do this automatically for every >> .csv in the working directory without my specifying each file. >> >> I'd appreciate any help or ideas you might have. >> >> Thanks! >> >> Mark Na >> > > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.