Hello R-list, I am preforming an lda on the following data.
Curvature Diameter Quality 1 2.95 6.63 Passed 2 2.53 7.79 Passed 3 3.57 5.65 Passed 4 3.16 5.47 Passed 5 2.58 4.46 NotPassed 6 2.16 6.22 NotPassed 7 3.27 3.52 NotPassed I use lda: > ddd<-lda(Quality~ Curvature+Diameter, data=momo) > ddd Call: lda(Quality ~ Curvature + Diameter, data = momo) Prior probabilities of groups: NotPassed Passed 0.5 0.5 Group means: Curvature Diameter NotPassed 2.633333 5.383333 Passed 3.016667 6.690000 AND lda$scaling: gives me LD1 Curvature 2.372923 Diameter 1.368995 My question is, I would like to calculate the % influence that 1 factor has vs the other meaning does 1 factor have 0.6 influence and the other have 0.4? TIA [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.