On Jul 5, 2009, at 10:50 AM, Uwe Ligges wrote:
David Winsemius wrote:
So if your values are calculated from other values then consider
using all.equal()
And repeated applications of the testing criteria process are
effective:
test[3,][which(names(test)=="C1"):(which(test[3,] == 0.0)-1)]
C1 C2 C3
3 0.52 0.66 0.51
(and a warning that does not seem accurate to me.)
In which(names(test) == "C1"):(which(test[3, ] == 0) - 1) :
numerical expression has 3 elements: only the first used
David,
# which(test[3,] == 0.0)
[1] 6 7 8
and in a:b a and b must be length 1 vectors (scalars) otherwise just
the first element (in this case 6) is used.
That leads us to the conclusion that writing the line above is not
really the cleanest way or you intended something different ....
Thanks, Uwe. I see my confusion. I did want 6 to be used and it looks
as though I would not be getting in truouble this way, but a cleaner
method would be to access only the first element of which(test[3, ] ==
0):
test[3,][ which(names(test) == "C1") : (which(test[3,] == 0.0)[1]-1) ]
David
Seems to me that all of the element were used. I cannot explain
that warning but am pretty sure it can be ignored.
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
