One additional thought. If the reason you want to do that is
just so that you can see the last few rows more easily then

tail(Data)

will display the last few rows or tail(Data, 10) will display
the last 10 rows.

On Thu, Jul 9, 2009 at 7:36 AM, Sergey Goriatchev<serg...@gmail.com> wrote:
> Hi, Gabor
>
> Thank you!
> That is exactly what I did, even before your email. :-)
>
> Regards,
> Sergey
>
> On Thu, Jul 9, 2009 at 12:52, Gabor Grothendieck<ggrothendi...@gmail.com> 
> wrote:
>> To display that object in reverse time order try this:
>>
>> as.data.frame(Data)[nrow(Data):1, ]
>>
>>
>> On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goriatchev<serg...@gmail.com> wrote:
>>> Hello everyone,
>>>
>>> Say I have zoo object
>>>
>>> x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1
>>> x <- zoo(rnorm(5), x.Date)
>>> y <- zoo(rt(5, df=2), x.Date)
>>> z <- zoo(rt(5, df=5), x.Date)
>>>
>>> Data <- merge(x,y,z)
>>>
>>> What should I do to make the latest values appear at the top?
>>>
>>> Thank you for your help!
>>>
>>> Regards,
>>> Sergey
>>>
>>> ______________________________________________
>>> R-help@r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>
>
>
>
> --
> I'm not young enough to know everything. /Oscar Wilde
> Experience is one thing you can't get for nothing. /Oscar Wilde
> When you are finished changing, you're finished. /Benjamin Franklin
> Tell me and I forget, teach me and I remember, involve me and I learn.
> /Benjamin Franklin
> Luck is where preparation meets opportunity. /George Patten
>

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