Dear useRs and developeRs,
I am struggling with a simple but not obviously solvable issue. Suppose I
have the following list of data.frames called 'tmp':
a <- data.frame(a=rnorm(10),b=letters[1:10])
(tmp <- list(a,a[1:4,],a[1:7,]))
It is known that all data.frames in this list have the same number of
columns (and this is a good thing). I want to build a bigger data.frame
consisting of all list-members, e.g. the result should look like:
(res <- rbind(tmp[[1]],tmp[[2]],tmp[[3]]))
The question is how could I do this most efficiently? My real list consist
of about 700 data.frames, each with with exactly 10 columns and plenty of
rows. The obvious for-loop solution is rather time consuming and therefore
I'm looking for something more efficient.
Thank you in advance,
AS.
ps: 'sapply' should somehow do the trick, doesn't it?
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