Gabor Grothendieck wrote:
>
> Try this:
>
> z <- x * y[row(x) + col(x)]
>
Thanks! yes, that's the ticket.
In testing out your solution, I noticed I described my problem wrongly.
Apologies to anyone I confused.
So a clarification for anyone trying to follow this:
The index for y should have been y[i+j-1]
Gabor's solution is correct for the question as asked, and it works just
fine when I apply it to what I *should* have asked:
z <- x * y[row(x) + col(x) -1]
Glen
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