I need to convert a date-style string: "2009-06-16 09:28:17.746" To its POSIX representation: 1245137297746
The function below converts my POSIX date to a string ... now I need to go backwards! render.t32 <- function(t32, tz = "CET") { timez <- ISOdatetime(1970,1,1,0,0,0, tz ="UTC")+t32/1000 return(format(timez,"%Y-%m-%d %H:%M:%OS3",tz="CET")) } > render.t32(1245137297746) [1] "2009-06-16 09:28:17.746" Have not succeeded in my attempts to understand POSIX and I thank you for your attention. ~Derek Derek N. Eder Gothenburg University Vigilance and Neurocognition Laboratory Medicinaregatan 8B Box 421 Gothenburg Sweden SE 405 30 tlf (031) 342-8261 mobil 0704 915 714 "The most dangerous thing in the jungle is not the snakes, the spiders, the tigers, ... The most dangerous thing in the jungle is your mind!" ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.