months<-c("jan","feb","mar","apr","may","jun",
"jul","aug","sep","oct","nov","dec")
sortorder<-order(as.numeric(date2[,2]),match(date2[,1],months))
date2[sortorder,]
is probably what you want.
megh wrote:
> I have following object :
>
>> date2
> [,1] [,2]
> [1,] "apr" "1992"
> [2,] "aug" "1992"
> [3,] "dec" "1992"
> [4,] "feb" "1992"
> [5,] "jan" "1992"
> [6,] "jul" "1992"
> [7,] "jun" "1992"
> [8,] "mar" "1992"
> [9,] "may" "1992"
> [10,] "nov" "1992"
> [11,] "oct" "1992"
> [12,] "sep" "1992"
> [13,] "apr" "1993"
> [14,] "aug" "1993"
> [15,] "dec" "1993"
> [16,] "feb" "1993"
> [17,] "jan" "1993"
> [18,] "jul" "1993"
> [19,] "jun" "1993"
> [20,] "mar" "1993"
> [21,] "may" "1993"
> [22,] "nov" "1993"
> [23,] "oct" "1993"
> [24,] "sep" "1993"
> [25,] "apr" "1994"
> [26,] "aug" "1994"
> [27,] "dec" "1994"
> [28,] "feb" "1994"
> [29,] "jan" "1994"
> [30,] "jul" "1994"
>
> Now I want to sort the elements like below, and want to get the index
> numbers of "date2" under following sorting scheme.
>
> "jan" "1992"
> "feb" "1992"
> "mar" "1992"
> ............
> "dec" "1992"
> "jan" "1993"
> "feb" "1993"
> "mar" "1993"
> ............
> "dec" "1993"
> "jan" "1994"
> "feb" "1994"
> "mar" "1994"
> ............
> "dec" "1994"
>
> Can anyone help me please?
--
Erich Neuwirth, University of Vienna
Faculty of Computer Science
Computer Supported Didactics Working Group
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