On Wed, Sep 16, 2009 at 1:35 PM, Henrique Dallazuanna <www...@gmail.com>wrote:
> Try this:
>
> sapply(theList, '[[', 'A')
>
Thanks Henrique - that is much more elegant.
Rainer
>
> On Wed, Sep 16, 2009 at 8:34 AM, Rainer M Krug <r.m.k...@gmail.com> wrote:
> > Hi
> >
> > I have a list which cosists out of dataframes of the same structure. Now
> I
> > want to extract one column (let's say column "A") from all dataframes and
> > have them in a matrix (or dataframe).
> >
> > At the moment I am doiong:
> >
> > d <- data.frame(A=runif(100), B=rnorm(100))
> > theList <- list(e1=d, e2=d, e3=d, e4=d)
> > f <- sapply(theList, function(l){l$A} )
> >
> > But I am sure ther is a more elegant way?
> >
> > Rainer
> >
> > --
> > Rainer M. Krug, Centre of Excellence for Invasion Biology, Stellenbosch
> > University, South Africa
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
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> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>
--
Rainer M. Krug, Centre of Excellence for Invasion Biology, Stellenbosch
University, South Africa
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